Question 5: Differentiate the functions with respect to x. sin ( ax+b)/cos (cx+d )
Class 12 - Math - Continuity and Differentiability
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4
Hiii...
Here is answer.....
Here is answer.....
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Answered by
10
Hey there.....
= y = sin(ax+b) / cos(cx+d)
=> d /dx = d/dx[sin ( ax+b)/cos (cx+d )]
By applying quotient and chain rule,
=> dy/dx = [ cos(cx+d). d/dx{sin(ax+b)} - sin(ax+b).d/dx{cos(cx+d)} ] / cos (cx+d)²
=> d/dx = [a cos(cx+d).cos(ax+b) + sin(ax+b).sin(cx+d).c] / cos (cx+d)²
Hope it helps...✌
= y = sin(ax+b) / cos(cx+d)
=> d /dx = d/dx[sin ( ax+b)/cos (cx+d )]
By applying quotient and chain rule,
=> dy/dx = [ cos(cx+d). d/dx{sin(ax+b)} - sin(ax+b).d/dx{cos(cx+d)} ] / cos (cx+d)²
=> d/dx = [a cos(cx+d).cos(ax+b) + sin(ax+b).sin(cx+d).c] / cos (cx+d)²
Hope it helps...✌
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