Question

Question 5 Find the number which bears the smae ratio to 7/33 that 81/21 does to 4/9... No spam

Answer 1

Answer:

Solution:

Let the required number x/y

Now, ratio of 8/21 to 4/9 = \frac{8/21}{4/9}

4/9

8/21

= 8/21×9/4=6/7

Thus, we have

$\frac{x/y}{7/33}$

=> x/y =

$\frac{6/7}{7/33} </p><p>$

=> x/y = 6/7 × 7/33

=> x/y = 2/11

Hence, the required number is 2/11.