Question 5.
In the given figure 1 || m. Find the values of a, b and c.
120
400V
Kb
m
b
45°
557
m
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i) In the triangle, the sum of all angles will be 180°
So 120°+40°+a = 180°
a=20°
Now, it is given that l ║ m.
So b=40° (Transversal angle)
a+b+c=180°(Straight Line)
20°+40°+c=180°
c=120°
ii)Similarly in 2nd one:-
45°+55°+b=180°
100°+b=180°
b=80°
c=55°(Transversal angle)
a=45°(Transversal angle)
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