question 5 pls say me fast
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sin(A+B)=1
sin(A+B)=sin90
A+B=90. ............ (1)
cos(A-B)=root3/2
cos(A-B)=cos30
A-B=30 .............. (2)
On solving eq.(1) and (2), we get
A=60 and B=30
sin(A+B)=sin90
A+B=90. ............ (1)
cos(A-B)=root3/2
cos(A-B)=cos30
A-B=30 .............. (2)
On solving eq.(1) and (2), we get
A=60 and B=30
Answered by
1
Sin(A+B) =1 =90 °
A+B=90°....(1)
Cos(A-B) =√3/2 =30°
A-B = 30° ...(2)
Adding 1 and 2
A+B = 90°
A-B = 30°
2A = 120
A=60°
From 1 B=30°
Therefore <A=60° and <B=30°
Sreyarroy:
thnss for marking as the brainliest answer
ur welcome
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