Math, asked by santoshigadam, 5 hours ago

Question 5
Prove that the fraction
7n+1/20n +3
is irreducible for every natural number n.​

Answers

Answered by twinklingstar19
4

Step-by-step explanation:

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Answered by olamideolajuyi19
3

Answer:

Suppose \frac{7n+1}{20n +3} = k

So

7n+1 = k(20n +3)\\(7 + 20k) n = 3k - 1\\n = \frac{3k - 1}{7 + 20k} \\

Since 3k - 1 < 7 + 20k, n is not a natural number

So, \frac{7n+1}{20n +3} is irreducible for every natural number n.

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