Question

Question 5 ..question 6 ... pls if u know only ques5 then send it or if u know only que 6 dont send it

Answer 1

Solution to your question

Answer 2

According to given sum,

5)

$= > \: \frac{ \sqrt{2} + \sqrt{5} }{ \sqrt{5} }$

$= > \: \frac{ \sqrt{2} + \sqrt{5} }{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} }$

$= > \: \frac{ \sqrt{10} + 5}{5}$

$= > \: \frac{3.162 + 5}{5}$

$= > \: \frac{8.162}{5}$

=> 1.6324

6)

Let 0.252525....... be x.

x=0.25252525........ (1)

Here the periodicity is 2 . So, multiply by 100 on both sides.

=> 100x= 25.25252525........ (2)

Subtract eq(1) from from (2), we get

100x-x = 25.25252525.......-(0.252525.....)

=> 99x=25

=> x=25/99.


:-)Hope it helps u.