Question 5 Solve these using suitable arrangement and properties a) 17 × 108 b) 102 × 103 c) 137 + 908 + 463
Answers
a) 17 * 108
17 * (100+8)
1700 + 136
=)1836
b) 102 * 103
(100+2) * (100+3)
100 * (100+3) + 2*(100+3)
(10000+300) + (200+6)
10300 + 206
=)10506
c) 137+908+463
(137+463)+908
600+908
1508
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Step-by-step explanation:
- 17 × 108 {this is called distributive property}
= 17 × (100 + 8) {split the 108 to get 100 + 8}
= (17 × 100) + (17 × 8) {as 17 is outside the brackets we multiply it with everything inside the brackets}
= (1700) + (136) {now we do addition}
= 1836
2. sorry I'm not sure about this one
3. 137 + 908 + 463
for this calculation, we use suitable rearrangement
(137 + 463) + 908 {we put 137 and 463 in the bracket because, when we take the ones digit's numbers that is 7 and 3, when we add them both get 10 so that is how you do suitable rearrangement}
(137 + 463) + 908
= (600) + 908
= 1508
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