Question

Question 5 :
Two resistors with resistances 5 and 10 respectively, are to be connected to a battery of emf 6V,
(a)How will you connect so as to obtain minimum current and maximum current?
(b)What will be the resistances in each case?
(c) Calculate the strength of the total current in the circuit in the two cases.​

Answer 1

Explanation:

(a) For obtaining minimum current, the two resistors should be connected in parallel.

(b) For obtaining maximum current, the two resistors should be connected in series.

(c) R¹ = 5Ω, R²= 10Ω, V = 6V

For Parallel Combination = 1/R = 1/R¹ + 1/R²

1/5 + 1/10 = 3/10

====> R = 10/3 Ω

Total current in the circuit,

I = V /R = 6×3/10 = 1.8 A

(iii) For series combination,

R = 5 + 10 = 15 Ω

Total current in the circuit,

I = V /R =6/15 = 0.4 A

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