Question

Question. 5
What is the value of y after evaluating the
expression y = y++ + y++ + - -y + ++y; when
int y=6?​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

• The value of y is - 28

Step By Step Solution:

Given that,

int y = 6;

>> y = y++ + y++ + --y + ++ y

>> y = 6 + y++ + --y + ++y  (y is 6 due to post-increment)

>> y = 6 + y++ + --y + ++y (y becomes 7 after increment)

>> y = 6 + 7 + --y + ++y (y is 7 due to post-increment)

>> y = 6 + 7 + --y + ++y (y becomes 8)

>> y =6 + 7 + 7 + ++y (y becomes 7 due to pre-decrement)

>> y = 6 + 7 + 7 + 8 (y becomes 8 due to pre-increment)

Adding up, we get,

>> y = 6 + 14 + 8

>> y = 20 + 8

>> y = 28

Hence, the final value of y is 28.