Question 5 Write the smallest digit and the greatest digit in the blank space of each of the following numbers so that the number formed is divisible by 3: (a) ___6724 (b) 4765 ___2
Class 6 - Math - Playing with Numbers Page 57
Answers
A number is divisible by 3 if its sum of all digits is divisible by 3
(a) ___6724
6+7+2+4= 19
if we add 2 then the digit is divisible by 3 ( 19+2=21)
2 is the smallest digit
26724 = 2 + 6 + 7 + 2 + 4 = 21
if we add 8 then the digit is divisible by 3 ( 19+8=27)
8 is the largest digit
26724 = 8+ 6 + 7 + 2 + 4 = 36
b) (b) 4765 ___2
4+7+6+5+2=24
if we add 0 then the digit is divisible by 3 ( 24+0=24)
0 is the smallest digit
4765 ___2 = 4+ 7+6+5+0+2= 24
if we add 9 then the digit is divisible by 3 ( 24+9=33)
9 is the largest digit
4765 ___2 =4+ 7+6+5+9+2= 33
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Hope this will help you
Answer:
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Step-by-step explanation:
(a)
The number is given as _6724.
The number is divisible by 3 if the sum of its digits is divisible by 3.
Adding the digits of the given number,
6+7+2+4=19
If 2 is added to the above number then the number will become 21 which is divisible by 3 and also, 2 is the smallest number that can fill the missing space.
Now, if 8 is added to the given number then the number will become 27 which is divisible by 3 and 8 is largest number that can make the given number divisible by 3.
Therefore, the smallest number will be 2 which will form 26724 and the largest number will be 8 forming 86724.
(b)
The number is given as 4765_2.
The number is divisible by 3 if the sum of its digits is divisible by 3.
Adding the digits of the given number,
4+7+6+5+2=24
If 0 is added to the above number then the number will become 24 which is divisible by 3 and also, 0 is the smallest number that can fill the missing space.
Now, if 9 is added to the given number then the number will become 33 which is divisible by 3 and 9 is largest number that can make the given number divisible by 3.
Therefore, the smallest number will be 0 which will form 476502 and the largest number will be 9 forming 476592.