Question

Question 51 pts If you had a 7% solution, (made famous by Sherlock Holmes), of dextrose, how many grams of dextrose would there be in 700 mL of the solution?

Answer 1

Answer:

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Explanation:

The mass of dextrose present in 700 mL of solution is 49 g.

Explanation:

It is given that 7 % of the solution contains dextrose. This means that 7 grams of dextrose is present in 100 mL of solution.

We need to find the amount of dextrose present in 700 mL of solution.

If in 100 mL of solution, 7 grams of dextrose is present.

So, in 700 mL, the amount of dextrose present will be =

$7g/100ml*700ml$ = 49

Hence, the mass of dextrose present in 700 mL of solution is 49 g.