Question 55:
The mass of a planet is 6 x 1024 kg and its diameter is 12.8 x 103 If the value of gravitational constant be 6.7 x 10-11 Nm2/kg2, calculate the value of acceleration due to gravity on the surface of the planet. What planet could this be ?
Lakhmir Singh Physics Class 9
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Answer:
A planet has a mass of 6×10^24 kgs.
It has a diameter of 12.8 ×10^3 km or 12.8 ×10^6m.
So according to the problem we have to find out the acceleration due to gravity of that planet.
Now, we know that gravitational value is constant, so it is 6.7×10^-11 Nm^2/Kg^2.
The formula to find acceleration due to gravity is :
g= G × (M/R^2)
Where g is the acceleration due to gravity, G is the gravitational constant M is the mass and R is the radius.
To find radius, we have to divide the diameter with 2.
So R will be (12.8×10^6/2)m
= 6.4 × 10^6 m.
So,
g= 6.7× 10^-11 × [6×10^24/(6.4 × 10^6)^2]
= 6.7 × 60/ 6.4× 6.4
= 9.8m/s^2
The planet is Earth as its acceleration due to gravity is 9.8m/s^2.
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