Question : 58
A person has Rs. 40000 out of which he puts Rs.
12000 at 10% SI for 3 years and Rs 16000 at 12.5%
Cl for 2 years and keeps the rest with himself. What
is the total amount with him after three years?
Answers
Answer
For the first 2 years
S.I.=
100
P×N×R
⇒S.I.= 100 16,000×2×20
⇒S.I.=6,400
Amount = S.I. + P
⇒Amount=6,400+16,000
⇒Amount=22,400
Amount in the account at the end of the two years is Rs. 22,400.
For the remaining one year.A=P(1+ 2×100r ) n×2 ⇒A=22,400(1+20020 ) 2⇒A=22,400( 1011 )2⇒A=27,104
The Amount collected by the person after 3 years is Rs 47,850.
Given,
Total Amount = Rs 40,000
Amount for SI = Rs 12,000
SI Rate = 10%
SI Time period = 3 years
The amount for CI = Rs 16000
CI Rate = 12.5%
SI Time period = 2 years
To Find,
Amount collected by the person after 3 years
Solution,
Amount left at the beginning = 40,000 - 12,000 - 16,000
Amount left at the beginning = 40,000 - 28,000
Amount left at the beginning = Rs 12,000
Amount generated by SI = Principal Amount + Simple Interest
Amount generated by SI = 12,000 +
where P is the Principal Amount
R is the Rate of Interest
T is Time Period
Amount generated by SI = 12,000 +
Amount generated by SI = 12,000 + 3,600
Amount generated by SI = Rs 15,600
Amount generated by CI =
where P is the Principal Amount
R is the Rate of Interest
T is Time Period
Amount generated by CI =
Amount generated by CI = 16000
Amount generated by CI = 16000 * (1.125)²
Amount generated by CI = 16000 * 1.265
Amount generated by CI = Rs 20,250
Total Amount after 3 years = Amount left at the beginning + Amount generated by SI + Amount generated by CI
Total Amount after 3 years = 12,000 + 15,600 + 20,250
Total Amount after 3 years = 47,850
Hence, the total amount the person has after 3 years is Rs 47,850.
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