Science, asked by DivyaSingh26, 1 month ago

Question :

(5x2 - 16x - 21) divided by (x + 1)

Solve it please

Answers

Answered by ᏞiteralFairy
39

\large\bf{\pink{\sf{Question}} }

\mathtt{(5x² - 16x - 21)÷(x + 1)}

\large\bf{\orange{Step \: by \: step \: \: explaination:-} }

\implies{\tt{\dfrac{(5x² - 16x - 21)}{(x + 1)}}}

\implies{\tt{\dfrac{(5x²+5x−21x−21)}{(x + 1)}}	}

{\implies{\tt{\dfrac{5x(x+1)−21(x+1)}{(x + 1)}\: \: \: \: taking \ 5x \: and\: -21\: common}}}

\implies{\tt{ \dfrac{(5x−21)(x+1)}{(x + 1)}}}

\implies{\tt{\dfrac{(5x−21) \cancel{(x+1)}}{ \cancel{(x + 1)}}}}

\implies{\tt{ (5x−21)}}⟹(5x−21)</p><p>

\sf{ \red{\therefore \ (5x−21)}\ wil\ get\ When\ we\ divide\ (5x² - 16x - 21) divided\ by\ (x + 1)}∴ (5x−21) wil  \: get  \: When  \: we  \: divide (5x²−16x−21)divided \:  by (x+1)

Answered by Anonymous
2

Answer:

\huge{\tt{\red{}\green{A}\purple{N}\pink{S}\blue{W}\orange{E}\red{R}}}

\huge\ \frac{ {(5x}^{2} - 16x - 21) }{(x + 1)}

 \huge\ \frac{ {(5x}^{2} + 5x - 21x - 21)}{(x + 1)}

 \huge\ \frac{5x(x + 1) - 21(x + 1)}{(x + 1)}

 \huge\ \frac{(5x - 21)(x + 1)}{(x + 1)}

\huge\ 5x - 21

Similar questions