Question

QUESTION :-
6.0g of sodium hydroxide is dissolved in 100g of water. Calculate the mass percent of sodium hydroxide in the solution.
Asked by - @ItzAdmire​

Answer 1

Answer:

5.6603 %

Explanation:

The solution's mass is 106g

The mass of NaOH is 6g

therefore ,

percentage of NaOH= (6/106)×100

= 5.6603%

Answer 2

Given:-

• Mass of Sodium Hydroxide ( NaOH ) is 6.0g.

• Mass of Water ( H₂O ) is 100g.

To Find:-

• Mass percent of Sodium Hydroxide ( NaOH ) in the solution.

Explanation:-

Here, Mass of Sodium Hydroxide is 6g that is solute.

Mass of Water is 100g that is solvent.

So, Total mass of Solution = Solvent + Solute

                                            = 100g + 6g

                                            = 106g

Now, Percent of Sodium hydroxide is

⇒ $\bigg(\dfrac{\sf{Mass\ of\ Solute}}{\sf{Mass\ of\ Solution}} \times 100 \bigg)$$\%$

⇒ $\bigg(\dfrac{\sf{6\ g}}{\sf{106\ g}} \times \sf{100} \bigg)$$\%$

⇒ $\sf{5.66\ }\%$

Hence, Percent of Sodium Hydroxide in the solution is  $\huge\text{5.66\ }\%$ .