Question 6.10: A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10 −4 T and the dip angle is 30°.
Class 12 - Physics - Electromagnetic Induction Electromagnetic Induction Page-230
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Given,
Speed of the jet plane towards west = 1800 km/h
In m/s, speed of the jet plane towards west,v = 1800 × 5/18 = 500 m/s
Length of the span of the jet plane = 25 m
Magnetic field = 5 × 10^-4 T
Dip angle =30°
The vertical component of Earth’s magnetic field can be calculated as follows: Bv= B sinδ
Bv= 5 × 10^-4 T × sin30°
⇒ Bv= 5 × 10^-4 T × 1/2
∴ Bv = 2.5 × 10^-4 Tesla
The voltage difference developed between the ends of the jet can be calculated using the formula:
e = (Bv) × l × v
e =2.5×10^-4 T× 25m × 500m/sec
e = 3.125 V
∴ the voltage difference developed between the ends of the wings is approximately 3V.
Speed of the jet plane towards west = 1800 km/h
In m/s, speed of the jet plane towards west,v = 1800 × 5/18 = 500 m/s
Length of the span of the jet plane = 25 m
Magnetic field = 5 × 10^-4 T
Dip angle =30°
The vertical component of Earth’s magnetic field can be calculated as follows: Bv= B sinδ
Bv= 5 × 10^-4 T × sin30°
⇒ Bv= 5 × 10^-4 T × 1/2
∴ Bv = 2.5 × 10^-4 Tesla
The voltage difference developed between the ends of the jet can be calculated using the formula:
e = (Bv) × l × v
e =2.5×10^-4 T× 25m × 500m/sec
e = 3.125 V
∴ the voltage difference developed between the ends of the wings is approximately 3V.
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