Question

question 6????????????

Answer 1

GIVEN:-
ABCD is a quadrilateral
TO PROVE :-
AB+BC+CD+DA>AC+BD
PROOF:-
In Triangle ABC
AB+BC>AC(sum of two side of a triangle is greater than 3rd side)......(EQ 1 )
In Triangle BCD
BC+CD>BD(same ,sum..... )....(EQ 2)
In Triangle ACD
CD+AD>AC ( same) ....(EQ 3)
ABIn Triangle BDC
AD+AB>BD (same).....(EQ4)

ADDING (EQ)
AB+BC+CD+DA+AB+BC+CD+CA>AD+BC+AD+AC
or 2(AB+BC+CD+AD)>2(AD+BC). ...... (2 cancel)
or. AB+BC+CD+AD>AD+BC. (HENCE PROVED)