Question 6.7: A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 m s −1 , at right angles to the horizontal component of the earth’s magnetic field, 0.30 × 10 −4 Wb m −2 . (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?
Class 12 - Physics - Electromagnetic Induction Electromagnetic Induction Page-230
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Given,
Length of the wire, l = 10 m
Speed of wire, v = 5.0 m/s
Magnetic field, B = 0.30 × 10^-4
Wb/m²
(a) The e.m.f induced in the wire can be calculated as follows:
e = Blv
where B is the magnetic field
l is the length of the loop and,
v is the velocity of the rectangular loop
substituting the values in above equation, we get,
e = 0.30 × 10^-4 Wb/m² × 10 m × 5m/s
e = 1.5 × 10^-3 V
(b) The direction of the induced emf will be from west to east in accordance with the Fleming’s right - hand rule.
(c) The east end of the straight wire will be having high electrical potential.
Length of the wire, l = 10 m
Speed of wire, v = 5.0 m/s
Magnetic field, B = 0.30 × 10^-4
Wb/m²
(a) The e.m.f induced in the wire can be calculated as follows:
e = Blv
where B is the magnetic field
l is the length of the loop and,
v is the velocity of the rectangular loop
substituting the values in above equation, we get,
e = 0.30 × 10^-4 Wb/m² × 10 m × 5m/s
e = 1.5 × 10^-3 V
(b) The direction of the induced emf will be from west to east in accordance with the Fleming’s right - hand rule.
(c) The east end of the straight wire will be having high electrical potential.
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