Question 6.9 Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. Molar heat capacity of Al is 24 J mol–1 K–1.
Class XI Thermodynamics Page 183
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Answered by
237
given mass of Al = 60g
Molar mass of Al = 27 g/mol
so, mole = given mass/molar mass
= 60/27 = 20/9
A/C to question,
Molar heat capacity (C) = 24J/mol/K
Temperature change (∆T) = (55°C - 35°C) = 20°C or 20K
Heat {Q} = n.C.∆T
= 20/9 × 24 × 20 J
= 1066.67 J
= 1.0667 KJ
Molar mass of Al = 27 g/mol
so, mole = given mass/molar mass
= 60/27 = 20/9
A/C to question,
Molar heat capacity (C) = 24J/mol/K
Temperature change (∆T) = (55°C - 35°C) = 20°C or 20K
Heat {Q} = n.C.∆T
= 20/9 × 24 × 20 J
= 1066.67 J
= 1.0667 KJ
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14
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