Question

Question 6:

A copper wire has diameter 0.5 mm and resistivity of 1.6 × 10–8 Ω m. What will

be the length of this wire to make its resistance 10 Ω? How much does the

resistance change if the diameter is doubled?​

Answer 1

Answer:

Step-by-step explanation:

Area of cross-section of the wire, A =π (d/2) 2

Diameter= 0.5 mm = 0.0005 m

Resistance, R = 10 Ω

We know that

∴ length of the wire = 122.72m

If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m

Let new resistance be Rʹ

∴ the new resistance is 2.5 Ω