"Question 6 A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. (i) What is the area of the glass? (ii) How much of tape is needed for all the 12 edges?
Class 9 - Math - Surface Areas and Volumes Page 213"
Answers
Answered by
413
1) Dimensions of greenhouse:
l = 30 cm, b = 25 cm, h = 25 cm
Total surface area of green house = 2(lb + bh + lh)
= 2(30×25 + 25×25 + 25×30)
= 4250cm2
(ii) Length of the tape needed = 4(l + b + h)
= 4(30 + 25 + 25)
= 320 cm
l = 30 cm, b = 25 cm, h = 25 cm
Total surface area of green house = 2(lb + bh + lh)
= 2(30×25 + 25×25 + 25×30)
= 4250cm2
(ii) Length of the tape needed = 4(l + b + h)
= 4(30 + 25 + 25)
= 320 cm
Answered by
364
Given: Dimensions of herbarium:
l = 30 cm, b = 25 cm, h = 25 cm
i) Area of the glass=Total surface area of herbarium
= 2(lb + bh + lh)
= 2(30×25 + 25×25 + 25×30)
= 2(750+625+750)
=2×2125
= 4250cm²
(ii) herbarium in in the shape of cuboid.
So Length of the required tape will be equal to total length of edges of cuboid.
Length of the tape= 4(l + b + h)
= 4(30 + 25 + 25) = 4× 80
= 320 cm.
Tape needed for all the 12 edges=320 cm
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Hope this will help you....
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