"Question 6 An umbrella is made by stitching 10 triangular pieces of cloth of two different colours (see the given figure), each piece measuring 20 cm, 50 cm and 50 cm. How much cloth of each colour is required for the umbrella?
Class 9 - Math - Heron's Formula Page 207"
Answers
Answered by
595
Hello
Here is your answer.
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Solution:-
_______
For pieces of triangle,
a = 20 cm , b = 50 cm , c = 50 cm
.°. s = a + b + c / 2
= 20 + 50 + 50 / 2
= 120 / 2
= 60 cm
.°. a triangles area = √ s ( s - a ) ( s - b ) ( s - c )
= √ 60 ( 60 - 20 ) ( 60 - 50 ) ( 60 - 50 )
= √ 60 ( 40 ) ( 10 ) ( 10 )
= 200√6 cm²
.°. one colour of five triangles area ,
= 5 ( 200√6 ) cm²
= 1000√6 cm²
so, there are 1000√6 cm² cloth of each colour is required for the umbrella.
thanks
========================================================================
Here is your answer.
========================================================================
Solution:-
_______
For pieces of triangle,
a = 20 cm , b = 50 cm , c = 50 cm
.°. s = a + b + c / 2
= 20 + 50 + 50 / 2
= 120 / 2
= 60 cm
.°. a triangles area = √ s ( s - a ) ( s - b ) ( s - c )
= √ 60 ( 60 - 20 ) ( 60 - 50 ) ( 60 - 50 )
= √ 60 ( 40 ) ( 10 ) ( 10 )
= 200√6 cm²
.°. one colour of five triangles area ,
= 5 ( 200√6 ) cm²
= 1000√6 cm²
so, there are 1000√6 cm² cloth of each colour is required for the umbrella.
thanks
========================================================================
nikitasingh79:
okk.
Answered by
50
There are 10 triangles, out of which 5 of black and 5 of grey color. Now,
Area of of each cloth=5× area of 1 triangle
Area of triangle=
s(s−a)(s−b)(s−c)
,s=
2
a+b+c
=
2
50+20+50
s=60㎝
∴ar△=
60(60−50)(60−20)(60−50)
=
60×10×40×10
=
6×10×10×4×10×10
=2×10×10
6
=200
6
㎠
Area of each cloth required=(5×200
6
)㎠=1000
6
㎠
Hope it help
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