Question 6 b part
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By cross multiplication,
A={(7×2)+(5×3)}=14+15=29
B={(7×0)+(4×-1)}=0-4=-4
C={(4×1)+(-1×0)}=4+0=4
NOW
AC+B2-10C
(29×4)+(-4)square-10×4
116+16-40=92
A={(7×2)+(5×3)}=14+15=29
B={(7×0)+(4×-1)}=0-4=-4
C={(4×1)+(-1×0)}=4+0=4
NOW
AC+B2-10C
(29×4)+(-4)square-10×4
116+16-40=92
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