Question

Question 6 find the resistance between the points A and B of the following networks​

Answer 1

Answer:

2 Ohms

Explanation

Rac and Rbc are in series.

Therefore, Racb = 3Ohm + 3Ohm = 6Ohms

Now Racb and Rab in parallel

Therefore 1/RAB = 1/Racb + 1/Rab

=1/6 + 1/3

= 3/6= 1/2

Therefore, RAB= 2 Ohms