Question

"Question 6 In the given figure, AC = AE, AB = AD and ∠BAD = ∠EAC. Show that BC = DE.
Class 9 - Math - Triangles Page 120"

Answer 1

Answer:

Step-by-step explanation:

In ΔABC and ΔADE

A

B

=

A

D

(given)

A

C

=

A

E

(given)

Since

∠

B

A

D

=

∠

E

A

C

So,

∠

B

A

D

+

∠

D

A

C

=

∠

E

A

C

+

∠

D

A

C

Or,

∠

B

A

C

=

∠

D

A

E

So, by SAS rule

Δ

A

B

C

≅

Δ

A

D

E

Or,

B

C

=

D

E

proved