Math, asked by vikrantsaini1998, 4 months ago

Question 6 of 20
A 30-litre mixture of kerosene and diesel contains
kerosene and diesel in the ratio of 5:1. 12 litres of the mixture are removed and replaced
with kerosene and the process is repeated one more time. At the end of two removals and replacements, what is the ratio of kerosene and
diesel in the resultant mixture?​

Answers

Answered by Anonymous
1

Answer:

The ratio of kerosene and

diesel in the resultant mixture=94:6

Step-by-step explanation:

30 LITRE MIXTURE

Kerosine=5*30/6=25 litre

Diesel=30-25=5 litre

Step I: Now 12 litre mixture removed

left miture=30-12=18

now Kerosine=5*18/6=15 litre

Diesel=18-15=3 litre

12 litre kerisine is added

so kerosene=15+12=27, diesel=3 litres

kerosene:diesel=27:3=9:1

=========================

Step II: Now 12 litre mixture removed

left mixture=30-12=18

now Kerosene=9*18/10=16.2 litre

Diesel=18-16.2=1.8 litre

12 litre kerosene is added

so kerosene=16.2+12=28.2, diesel=1.8 litres

Total=28.2+1.8=30 same

Thus Final ratio

Kerosene:Diesel: =28.2:1.8

=282:18=94:6

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