Question

Question 6 please.. correct answer brainliest

Answer 1

In figure.6.40, angle X = 62 °,angle XYZ=54°. If YO and ZO are the bisectors of angle XYZ and angle XYZ respectively of triangle XYZ,find angle OZY and angle YOZ.

In ∆XYZ,

Angle X=62°

Angle XYZ=54°

you have given in question (text)

angle X + angle xyz + angle Z = 180°

angle addition property of triangle

62 + 54 + angle Z = 180°

116 + angle z = 180°

angle Z = 180 - 116

angle Z = 64°

OZ is angle bisector of angle XZY

angle OZY = 32° 1

similarly OY is angle bisector of angle XYZ

angle OYZ= 27° 2

in triangle OYZ,

angle OYZ+ angle OZY+ angle YOZ=180°

angle sum property of triangle

27 + 32 + angle YOZ= 180

59 + angle YOZ = 180

angle YOZ= 121°

ANS: angle OZY=32°

angle YOZ= 121°

Answer 2

Answer:

Angle OZY=62°

Angle YOZ=60°

Step-by-step explanation:

In ∆XYZ

Angle X+ Angle Y+ Angle Z =180° { Angle Sum Property}

60°+58°+Z=180°

118°+Z=180°

Z=180°-118°

Z=62°

Now angle OZY=62°

In ∆OYZ

Angle O+Angle Y+Angle Z=180°

O+58°+62°=180°

O+120°=180°

O=60°

Now angle YOZ=60°