Question 61 in the attached picture
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4R/3
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Zahid2003:
That’s wrong .. the answer is 3R/4
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the answer is (d) 3R
FIRSTLY
AFTER A THERE IS R AND DOWN R ARE in parallel
aND there is again R with down R ARE IN SERIES and ano ther R WITH UPPER R ARE IN SERIES
THIS MAKES 2R AND 2R ARE IN PARALLEL
This makes resistance R
NOW this R AND WITH A R AND B R ARE IN SERIES
Now the resistance across the circuit ir 3R
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