Question

Question 66
If a +b+c=5 and ab + bc + ca = 4, then a' + 8 +3 - 3abe is equal to:​

Answer 1

Answer:

hey, ur question is wrong

it is a+b+c=5,

ab+bc+ca=10

Step-by-step explanation:

we know ,

a³ + b³ + c³ -3abc = (a + b + c )(a² + b² + c² -ab -bc-ca)

now ,

a + b + c = 5

ab + bc + ca = 10

(a + b + c)² = a² + b² + c² +2(ab + bc+ca)

(5)² -2×10 = a² + b² + c²

a² + b² + c² =5

hence ,

a³ + b³ +c³ -3abc = ( a + b + c )(a² + b² + c² -ab- bc-ca)

=( 5)( 5 - 10) = 5 × (-5) = -25

Answer 2

Answer:

yes rishu8163 is correct

we hadn't read the chapter

Step-by-step explanation: