Question 68:
An element A has an atomic number of 6. Another element B has 17 electrons in its one neutral atom.
(a) n which groups of the periodic table would you expect to find these elements ?
(b) What type of bond is formed between A and B ?
(c) Suggest a formula of the compound formed between A and B.
Lakhmir Singh Chemistry Class 10
Answers
Answered by
4
a) group 14- atomic number 6
group 17 - 17 electrons in nuetral atom
b) covalent bond-
c) ab4
(the compounds are
Carbon - atomic number 6
chlorine- 17 electrons in nuetral atom)
group 17 - 17 electrons in nuetral atom
b) covalent bond-
c) ab4
(the compounds are
Carbon - atomic number 6
chlorine- 17 electrons in nuetral atom)
Answered by
1
Answer: (a) Carbon whose atomic no. is 6 belongs to 14th group.
(b) Carbon is non-metal and nitrogen is also non metals so, carbon and nitrogen formed covalent bond. Because non metal combine with non metal to form covalent bond.
(c) The compound form between A and B is neutral compound
Explanation:
Similar questions