Question

Question 7.2 What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2]= 0.60 M, [O2] = 0.82 M
and [SO3] = 1.90 M ?
2SO2(g) + O2(g) <---> 2SO3(g)

Class XI Equilibrium Page 224

Answer 1

2SO2(g) + O2(g) <=> 2SO3(g)

Given, conc. of SO2 = [ SO2] = 0.6 M
conc. of O2 = [ O2 ] = 0.82 M
conc. of SO3 = [ SO3 ] = 1.90 M

so, equilibrium constant ( Kc) = [SO3]²/[O2][SO2]²
= (1.9)²/0.82 × 0.6
= 12. 2289 M^-1 ≈ 12.23 /M

hence, equilibrium constant = 12.23 /M

Answer 2

hope it's helpful ..