Question

Question 7.4: A 60 μF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.

Class 12 - Physics - Alternating Current Alternating Current Page-266

Answer 1

Capacitance ( c ) = 60 цF = 60 * 10⁻⁶ F

Voltage ( v ) = 110 V

Frequency ( f ) = 60 Hz

Angular Frequency ( w ) = 2π * f = 2πf

Capacitive Reactance ( xc ) = 1 / wc

=> 1 / 2πf * c

=> 1 / 2π * 60 * 60 * 10⁻⁶

=> 1 / 2π * 36 * 10⁻⁴

RMS value of current :

I = v / xc

=> 220 / 2π * 36 * 10⁻⁴

=> 2.49 A

Thus RMS value of current is 2.49 A.