Question

Question 7.50 The degree of ionization of a 0.1M bromoacetic acid solution is 0.132. Calculate the pH of the solution and the pKa of bromoacetic acid.

Class XI Equilibrium Page 229

Answer 1

I hope this answer is right and brainlist

Answer 2

Answer: pH of solution is = 1.88

$p_{K_a}$ of bromo acetic acid = 2.69

Explanation:

$BrCH_2COOH\rightarrow BrCH_2COO^-+H^+$

 cM              0             0

$c-c\alpha$        $c\alpha$          $c\alpha$  

So dissociation constant will be:

$K_a=\frac{(c\alpha)^{2}}{c-c\alpha}$

Give c= 0.1 M and $\alpha$ = 0.132

$K_a=\frac{(0.1\times 0.132)^2}{(0.1-0.1\times 0.132)}=0.002$

$pK_a=-log[K_a]$

$pK_a=-log[0.002]=2.69$

Also $pH=-log[H^+]$

$[H^+]=c\alpha=0.1\times 0.132=0.0132M$

$pH=-log[0.0132]=1.88$