Math, asked by sajitazis3427, 6 months ago

Question 7
An architect presents a 3 inch wide by 4 inch deep by 3 inch tall model of a new central campus dorm. If the final building foundation is 126 feet wide, how deep (in feet) will the building be?

Answers

Answered by FireBird2723
3

Answer:

168 feet deep

Step-by-step explanation:

The ratio between the height width and depth is given to be 3:3:4

Let the dimensions be 3x, 3x and 4x respectively,

The width of the final foundation of the building is given to be 126 feet wide.

Therefore, 3x = 126

=> x = 126/3

= 42

As x= 42, the depth of the foundation will be equal to:

4x= 4×42

= 168 feets.

Therefore, The building will be 168 feets deep.

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