Math, asked by BrainlyHelper, 1 year ago

Question 7 Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.

Class 10 - Math - Introduction to Trigonometry Page 190

Answers

Answered by sweety70
315
Heya,

sin 67° + cos 75 °

= cos 23° + sin 15°

This is according to the formula,

sin(90-∅) = cos∅ and
 
cos (90-∅) = sin Ф

Hope it helps u........
Answered by Anonymous
263
heya bhai !!

here is your answer

given

sin67° + cos75°

= sin ( 90° - 23° ) + cos ( 90° - 15° )

= cos 23° + sin15°

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