Question 7 Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
Class 10 - Math - Introduction to Trigonometry Page 190
Answers
Answered by
315
Heya,
sin 67° + cos 75 °
= cos 23° + sin 15°
This is according to the formula,
sin(90-∅) = cos∅ and
cos (90-∅) = sin Ф
Hope it helps u........
sin 67° + cos 75 °
= cos 23° + sin 15°
This is according to the formula,
sin(90-∅) = cos∅ and
cos (90-∅) = sin Ф
Hope it helps u........
Answered by
263
heya bhai !!
here is your answer
given
sin67° + cos75°
= sin ( 90° - 23° ) + cos ( 90° - 15° )
= cos 23° + sin15°
===================================
here is your answer
given
sin67° + cos75°
= sin ( 90° - 23° ) + cos ( 90° - 15° )
= cos 23° + sin15°
===================================
Similar questions