Question

Question 7 Find the 17th term in the following sequence whose nth term is an = 4n-3; a17, a24

Class X1 - Maths -Sequences and Series Page 180

Answer 1

$a_n=4n-3\\\\\\17th-term(a_{17})=4(17)-3\\a_{17}=68-3\\a_{17}=65\\\\24th-term(a_{24})=4(24)-3\\a_{24}=96-3\\a_{24}=93$

Answer 2

a17 = 65              a24 = 93

Given:

an = 4n - 3

To Find:

The value of a17 and a24

Calculating:

an = 4n - 3

Putting the value of n as 17 in the given equation above:

a17 = (4)(17) - 3

a17 = 68 - 3

a17 = 65

Therefore, the value of a17 is 65 if the value of nth term is given by an = 4n -3.

Now to Find the value of a24

an = 4n -3

Putting the value of n as 24 in the given equation above:

a24 = 4(24) - 3

a24 = 96 - 3

a24 = 93

Therefore, the value of a24 is 93 if the value of nth term is given by an = 4n -3.