Question

Question 7 Find the equation of a line drawn perpendicular to the line x/4 + y/6 = 1 through the point, where it meets the y-axis.

Class X1 - Maths -Straight Lines Page 233

Answer 1

Here, equation of line is
x/4 + y/6 = 1
(3x + 2y)/12 = 1
3x + 12y = 12 -------------(1)

if line (1) meet Y-axis . then put x = 0 in equation (1) , we get
0 + 2y = 12
y = 6
so, point is (0, 6)

now, equation of line perpendicular to equation (1) is
2x - 3y + K = 0 [ we know, if ax + by + c = 0 then perpendicular line of it is bx -ay + K ]

A/C to question,
line : 2x - 3y + K = 0 passes through the point (0, 6) so, it will satisfy.
e.g. 2 × 0 - 3 × 6 + K = 0
- 18 + K = 0
K = 18

hence, equation of line is 2x - 3y + 18 = 0

Answer 2

Answer:

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