Math, asked by panesarh989, 9 months ago

Question 7 If X/Y + Y/X = -1 (x,y # 0) then value of X^3-Y^3 is​

Answers

Answered by Asanhmr
0

Answer: 0

Step-by-step explanation:

X/Y + Y/X = -1

X^2+Y^2/XY= -1

X^2+Y^2= -XY

X^2+Y^2+XY= 0 ............ (1)

Using formula, a^3-b^3= (a+b) (a^2-ab+b^2)

X^3-Y^3 = (X-Y) (X^2Y^2+XY)

= (X-Y) × 0 = 0 (Using (1)

Answered by SweetPoison7
0

Answer: 0

Step-by-step explanation:

X/Y + Y/X = -1

X^2+Y^2/XY= -1

X^2+Y^2= -XY

X^2+Y^2+XY= 0 ............ (1)

Using formula, a^3-b^3= (a+b) (a^2-ab+b^2)

X^3-Y^3 = (X-Y) (X^2Y^2+XY)

= (X-Y) × 0 = 0 (Using (1)

Thanks!!!!

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