"Question 7 In a right triangle ABC,∠B = 90°. (a) If AB = 6 cm, BC = 8 cm, find AC (b) If AC = 13 cm, BC = 5 cm, find AB
Class 8 Squares and Square Roots Page 107"
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Pythagoras Theorem:
In a right-angled triangle, The sum of squares of the lengths of the two sides( base & perpendicular) is equal to the square of the length of the hypotenuse .
Hypotenuse is the longest side.
P is perpendicular, B is base , H is hypotenuse
H² = P² + B²
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Solution:
[Fig. is in the attachment]
a)
AC²= AB² + BC² [by Pythagoras Theorem]
= 6² + 8²
= 36 + 64
AC²= 100
AC= √100
AC= 10
(b) If AC = 13 cm, BC = 5 cm, find AB
AB²= AC²- BC² [by Pythagoras Theorem]
= 13²- 5²
= 169 – 25
AB²= 144
AB =√ 144
AB= 12
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Hope this will help you...
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