Question

Question.7 of short answers...
anvesha..tum kis school me ho or tumhra surname kya hai??

Answer 1

Answer:

Step-by-step explanation:

A=(2,-2)

B = (-2,1)

C = (5,2)

Using distance formula, finding the distance AB

$\orange { = \sqrt{(x_{2}-x_{1})^{2} + (y_{2} - y_{1})^{2}}}$

$= \sqrt{(-2-2)^{2} + [1 - (-2]^{2}}$

$= \sqrt{(-4)^{2} + 3^{2}}$

$= \sqrt{ 16 + 9 }$

$= \sqrt{25}$$=5$

Using distance formula, finding the distance BC

$= \sqrt{[5-(-2)]^{2} + (2- 1)^{2}}$

$= \sqrt{7^{2} + 1^{2}}$

$= \sqrt{ 49 + 1 }$

$= \sqrt{50}$

$=5\sqrt{2}$

Using distance formula, finding the distance AC

$= \sqrt{3^{2} + 4^{2}}$

$= \sqrt{ 9 + 16 }$

$= \sqrt{25}$

$=5$

$AB^{2} = 25$

$BC^{2} = 50$

$CA^{2} = 25$

$BC^{2} = AB^{2} + CA^{2}$    [Hence ABC is a right angles triangle]