Question

question 7 pls tell ​

Answer 1

Answer:

Area of Parallelogram = Base × Height

= AB × AX

Therefore,

$9 \frac{1}{3} = 7 \times AX$

$→AX = \frac{ \frac{28}{7} }{ 3}$

$→AX = \frac{4}{3} = 1 \frac{1}{3} cm$

Similarly, Area for parallelogram ABCD is also equals to BC × CY.

$→9 \frac{1}{3} = 4 \times CY$

$→CY = \frac{ \frac{28}{3} }{4} = \frac{28}{12} = 2 \frac{1}{3} cm$

Hope you got your answer

Have a great day ahead