Question 7: Prove tan¯¹ 63/16 = sin¯¹ 5/13 + cos¯¹ 3/5
Class 12 - Math - Inverse Trigonometric Functions
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Answered by
6
cos^2a=1-sin^2aormula use .
a=sin^-1 5/13. same do apply formula u get
a=sin^-1 5/13. same do apply formula u get
Answered by
34
To prove :
⇒ tan¯¹ 63/16 = sin¯¹ 5/13 + cos¯¹ 3/5
Taking R.H.S. :
⇒ sin¯¹ 5/13 + cos¯¹ 3/5
⇒ tan¯¹ 5/12 + tan¯¹ 4/3
⇒ tan¯¹ [ ( 5/12 + 4/3 ) / ( 1 - 5/12 ×4/3 ) ]
⇒ tan¯¹ [ { (15 + 48)/36 } / { (36 - 20) / 36 } ]
⇒ tan¯¹ (63 / 13)
Hope it helps!!!
⇒ tan¯¹ 63/16 = sin¯¹ 5/13 + cos¯¹ 3/5
Taking R.H.S. :
⇒ sin¯¹ 5/13 + cos¯¹ 3/5
⇒ tan¯¹ 5/12 + tan¯¹ 4/3
⇒ tan¯¹ [ ( 5/12 + 4/3 ) / ( 1 - 5/12 ×4/3 ) ]
⇒ tan¯¹ [ { (15 + 48)/36 } / { (36 - 20) / 36 } ]
⇒ tan¯¹ (63 / 13)
Hope it helps!!!
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