Question:7) Rajesh rode his bicycle from hom city which is 4km away. It took him 9min time to reach city. In return journey he rode home using a shorter route of 3km. This only took him 6min. What was the average speed in km/hr. for the journey home to city and back
please solve this
Answers
cos thita + sin thita =1
hope it helps you
Solution :-
given that ,
→ Distance = 4 km
→ Time taken to reach city = 9 min .
also,
→ Distance covered in return journey = 3 km
→ Time taken = 6 min .
So,
→ Total distance covered = 4 + 3 = 7 km
→ Total time taken = 9 + 6 = 15 minutes .
therefore,
→ Average speed = Total distance covered / Total time taken = (7/15) km / min .
now,
→ Distance covered in 1 min = (7/15) km
→ Distance covered in 60 min = (7/15) * 60 = 28 km .
Hence, the average for the journey home to city and back is 28 km/hr .
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