Question

QUESTION 7!!

UP THRERE ^^
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Answer 1

Step-by-step explanation:

$\frac{ \sqrt{3} + 1 }{ \sqrt{3} - 1} \\ \\ = (\frac{ \sqrt{3} + 1 }{ \sqrt{3} - 1} )( \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1} ) \\ \\ = \frac{ {( \sqrt{3} + 1)}^{2} }{3 - 1} \\ \\ = \frac{4 + 2 \sqrt{3} }{2} \\ \\ = 2 + \sqrt{3} \\ \\ a = 2 \\ \\ b = 1$

Hope it helps.

Answer 2

first u need to rationalize the denominator & then then solve it

here it is