Question

Question 7 Using Binomial Theorem, evaluate (102)^5

Class X1 - Maths -Binomial Theorem Page 167

Answer 1

 (102)^5 =(100+2)^5 Using binomial theorem, =(1×100^5×2^0) + (5×100^4×2^1) + (10×100^3×2^2) + (10×100^2×2^3) + (5×100^1×2^4) + (1×100^0×2^5)  =(10000000000) + (1000000000) + (40000000) + (800000) + (8000) + (32)  =11040808032  Hope this helps :-)