Question

Question:
(789*789*789 + 211*211*211)/ (789*789-789×211+211*211)​

followed by
(a3+b3)/(a2-ab+b2)

Answer 1

Answer:

let 789 be 'a'

and 211 be'b'

so , according to the question

(a³+b³)/(a²-ab+b²)

since (a²+b³)=(a+b)( a²-ab+b²)

(a+b)(a²-ab+b²)/(a²-ab+b²)

a+b

(789+211)=1000