Question 8.13: Use the formula λm T= 0.29 cm K to obtain the characteristic temperature ranges for different parts of the electromagnetic spectrum. What do the numbers that you obtain tell you?
Class 12 - Physics - Electromagnetic Waves Electromagnetic Waves Page-287
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According to Wein's displacement law,
λm × T = 0.29 cm K
or λm = (0.29/T) cm
where T is the temperature and λm is the maximum wavelength of the wave.
For different values of maximum wavelengths such as λm = 10-4 cm, 5 × 10-5 cm and 10-6 cm, the values for temperatures can be calculated as follows:
T = (0.29/λm) K
case 1 :- When, λm = 10-4 cm
T = 0.29/10-4 cm K
T = 2900 K
case 2 :- When, λm = 5× 10-5 cm
T = cm K
T = 5800 K
case 3 :- When, λm = 10-6 cm
T = 0.29/10-6 cm K
T = 290000 K
The above data shows that temperature is required to get radiations of different parts of electromagnetic spectrum and the temperature increases with decrease in the wavelength.
λm × T = 0.29 cm K
or λm = (0.29/T) cm
where T is the temperature and λm is the maximum wavelength of the wave.
For different values of maximum wavelengths such as λm = 10-4 cm, 5 × 10-5 cm and 10-6 cm, the values for temperatures can be calculated as follows:
T = (0.29/λm) K
case 1 :- When, λm = 10-4 cm
T = 0.29/10-4 cm K
T = 2900 K
case 2 :- When, λm = 5× 10-5 cm
T = cm K
T = 5800 K
case 3 :- When, λm = 10-6 cm
T = 0.29/10-6 cm K
T = 290000 K
The above data shows that temperature is required to get radiations of different parts of electromagnetic spectrum and the temperature increases with decrease in the wavelength.
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