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Question 8.9: The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula E = hν (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?

Class 12 - Physics - Electromagnetic Waves Electromagnetic Waves Page-286

Answers

Answered by abhi178
1
The photons of given we energy are released during transition between energy levels in the atomic and the emitted photon energy is equal to difference of energies of energy levels , among which transition has taken place.
For example photon energy for,
\lambda=1m can be calculated.
then, E = \frac{hc}{\lambda}
= (6.63 × 10^-34 × 3 × 10^8)/1 J
= 19.88 × 10^-26/1.6 × 10^-19 eV
= 12.425 × 10^-7 eV

so, for emission of radio waves the energy difference between energy levels should be 12.425 × 10^-7 eV
similarly, photon energy for other wavelength can be calculated as shown in figure.
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