Question 8 A bag contains 5 black and 6 red balls. Determine the number of ways in which 2 black and 3 red balls can be selected.
Class X1 - Maths -Permutations and Combinations Page 153
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A bag contains 5 black and 6 red balls .
number of ways of selection 2 black balls from 5 black balls = 5C2
number of ways of selection 3red balls from 6 red balls = 6C3
a/c to fundamental principle of counting,
total number of selection = 5C2 × 6C3
= 5!/2!(5-3)! × 6!/3!(6-3)!
= 5 × 4/2 × 6 × 5 × 4/6
= 10 × 20
= 200 ways .
number of ways of selection 2 black balls from 5 black balls = 5C2
number of ways of selection 3red balls from 6 red balls = 6C3
a/c to fundamental principle of counting,
total number of selection = 5C2 × 6C3
= 5!/2!(5-3)! × 6!/3!(6-3)!
= 5 × 4/2 × 6 × 5 × 4/6
= 10 × 20
= 200 ways .
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