Question

"Question 8 If the triangle ABC in the Question 7 above is revolved about the side 5 cm, then find the volume of the solid so obtained. Find also the ratio of the volumes of the two solids obtained in Questions 7 and 8.

Class 9 - Math - Surface Areas and Volumes Page 233"

Answer 1

On revolving the right angled  ⃤  ABC along the side 5 cm, we get a cone of radius(r)= 12 cm, height(h) 5 cm, and slant height(l) =13 cm will be formed.

Volume of solid so obtained(V1) =1/3 πr²h

= (1/3 × π × 12 × 12 × 5)

V1= 240π cm³

 

In the previous question , the volume V2 obtained by revolving ∆ABC about the side 12 cm.

V2 = 100π cm³

Ratio of the volumes =

V2/V1

=100π/240π

=10/24

=5/12 = 5:12

Hence, the required ratio is 5:12.

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Hope this will help you....

 

Answer 2

Answer:

here is your answer it might help you